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python3.4中的post请求怎么写

from urllib import request request.urlopen() def post(url, data=None, headers=None, timeout=2, decode='utf-8'): rt = HttpReturn() if headers is None: headers = {} post_data = urllib.parse.urlencode(data).encode(decode) try: req...

from urllib import request request.urlopen() 1234567891011121314 def post(url, data=None, headers=None, timeout=2, decode='utf-8'): rt = HttpReturn() if headers is None: headers = {} post_data = urllib.parse.urlencode(data).enc...

python3使用 from urllib import request request.urlopen()

python发送post和get请求get请求:使用get方式时,请求数据直接放在url中。方法一、import urllibimport urllib2url = "http://192.168.81.16/cgi-bin/python_test/test.py?ServiceCode=aaaa"req = urllib2.Request(url)print reqres_data = url...

用requests库 import requestsdata={} #表单为json格式,自定义requests.post(url,data=data)

import urllib2 import urllib #定义一个要提交的数据数组(字典) data = {} data['username'] = 'zgx030030' data['password'] = '123456' #定义post的地址 url = '' post_data = urllib.urlencode(data) #提交,发送数据 req = urllib2.urlopen...

可以参考如下三种方法: 一、application/x-www-form-urlencoded import urlliburl = "http://www.example.com"body_value = {"package": "com.tencent.lian","version_code": "66" }body_value = urllib.urlencode(body_value)request = urllib...

import urllib urllib2 url=" " #所要请求数据的url parameters={ } #参数形式 : “name" : "value",参数多余一个用,相隔 data=urllib.urlencode(parameters) request=urllib2.Request(url,data) response=request.urlopen(request)

调用requests库,发送post请求,通过data参数来传递 import requestspayload = {'a':'杨','b':'hello'}r = requests.post("http://httpbin.org/post", data=payload)print r.text

如果能使用第三方库,用requests在简单不过了 import requestsurl = 'https://...'payload = {'key1': 'value1', 'key2': 'value2'}r = requests.post(url, data=payload)如果不能: import urllib2, urllib url = 'https://...'payload = {'key...

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